-150=-16t^2+50t

Solution for -150=-16t^2+50t equation:

-150=-16t^2+50t

We move all terms to the left:

-150-(-16t^2+50t)=0

We get rid of parentheses

16t^2-50t-150=0

a = 16; b = -50; c = -150;
Δ = b2-4ac
Δ = -502-4·16·(-150)
Δ = 12100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12100}=110$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-110}{2*16}=\frac{-60}{32}
=-1+7/8
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+110}{2*16}=\frac{160}{32}
=5
$